04-树6 Complete Binary Search Tree
A Binary Search Tree (BST) is recursively defined as a binary tree which has the following properties: The left subtree of a node contains only nodes with keys less than the node&#……
05-树9 Huffman Codes
In 1953, David A. Huffman published his paper “A Method for the Construction of Minimum-Redundancy Codes”, and hence printed his name in the history of computer science……
06-图1 列出连通集
题目很简单，我没用教材上给的图结构，不然太麻烦了，这是个无加全的无向图。。。一个二维数组就搞定了 #include<iostream> #include<malloc.h> #include<queue> #define max 50 usin……
03-树3 Tree Traversals Again
An inorder binary tree traversal can be implemented in a non-recursive way with a stack. For example, suppose that when a 6-node binary tree (with the keys numbered from 1 to 6) is……
04-树5 Root of AVL Tree
An AVL tree is a self-balancing binary search tree. In an AVL tree, the heights of the two child subtrees of any node differ by at most one; if at any time they differ by more than……
04-树7 二叉搜索树的操作集
本题要求实现给定二叉搜索树的5种常用操作。 函数接口定义： BinTree Insert( BinTree BST, ElementType X ); BinTree Delete( BinTree BST, ElementType X ); Position Find( BinTree BST, ElementType X ); Position Find……
04-树4 是否同一棵二叉搜索树
给定一个插入序列就可以唯一确定一棵二叉搜索树。然而，一棵给定的二叉搜索树却可以由多种不同的插入序列得到。例如分别按照序列{2, 1, 3}和{2, 3, 1}插入初始为空的二叉搜索树，都得到一样的结果。于是对于输入的各种插入序列，你需要判断它们是否能生成一样的二叉搜索树。 输入格式: 输入包含若干组测试数据。每组数据的第1行给出两个正整数N (≤10)和L，……
哈夫曼树与哈夫曼编码
哈夫曼树的定义： 哈夫曼编码的定义： //构造哈夫曼树和哈夫曼编码的算法 #include <stdio.h> #include <string.h> #define N 50 //叶子结点数 #define M 2*N-1 //树中结点总数 type……
03-树2 List Leaves
Given a tree, you are supposed to list all the leaves in the order of top down, and left to right. Input Specification: Each input file contains one test case. For each case, the f……
03-树1 树的同构
给定两棵树T1和T2。如果T1可以通过若干次左右孩子互换就变成T2，则我们称两棵树是“同构”的。例如图1给出的两棵树就是同构的，因为我们把其中一棵树的结点A、B、G的左右孩子互换后，就得到另外一棵树。而图2就不是同构的。 现给定两棵树，请你判断它们是否是同构的。 输入格式: 输入给出2棵二叉树树的信息。对于每棵树，首先在一行中给出一个非负整数N (≤10)……
02-线性结构3 Reversing Linked List
Given a constant K and a singly linked list L, you are supposed to reverse the links of every K elements on L. For example, given L being 1→2→3→4→5→6, if K=3, then you must output ……